Modelica.Thermal.FluidHeatFlow.Examples

Examples that demonstrate the usage of the FluidHeatFlow components

Information

This package contains test examples:

1.SimpleCooling: heat is dissipated through a media flow
2.ParallelCooling: two heat sources dissipate through merged media flows
3.IndirectCooling: heat is disspated through two cooling cycles
4.PumpAndValve: demonstrates usage of an IdealPump and a Valve
5.PumpDropOut: demonstrates shutdown and restart of a pump
6.ParallelPumpDropOut: demonstrates shutdown and restart of a pump in a parallel circuit
7.OneMass: cooling of a mass (thermal capacity) by a coolant flow
8.TwoMass: cooling of two masses (thermal capacities) by two parallel coolant flows

Main Authors:

Anton Haumer
Technical Consulting & Electrical Engineering
A-3423 St.Andrae-Woerdern, Austria
email: a.haumer@haumer.at

Dr.Christian Kral
Austrian Institute of Technology, AIT
Giefinggasse 2
A-1210 Vienna, Austria

This Modelica package is free software and the use is completely at your own risk; it can be redistributed and/or modified under the terms of the Modelica License 2. For license conditions (including the disclaimer of warranty) see Modelica.UsersGuide.ModelicaLicense2 or visit http://www.modelica.org/licenses/ModelicaLicense2.

Extends from Modelica.Icons.ExamplesPackage (Icon for packages containing runnable examples).

Package Content

Name Description

SimpleCooling Example: simple cooling circuit

ParallelCooling Example: coolig circuit with parallel branches

IndirectCooling Example: indirect cooling circuit

PumpAndValve Example: cooling circuit with pump and valve

PumpDropOut Example: cooling circuit with drop out of pump

ParallelPumpDropOut Example: cooling circuit with parallel branches and drop out of pump

OneMass Example: ccoling of one hot mass

TwoMass Example: cooling of two hot masses

Utilities Utility models for examples

Name	Description
SimpleCooling	Example: simple cooling circuit
ParallelCooling	Example: coolig circuit with parallel branches
IndirectCooling	Example: indirect cooling circuit
PumpAndValve	Example: cooling circuit with pump and valve
PumpDropOut	Example: cooling circuit with drop out of pump
ParallelPumpDropOut	Example: cooling circuit with parallel branches and drop out of pump
OneMass	Example: ccoling of one hot mass
TwoMass	Example: cooling of two hot masses
Utilities	Utility models for examples

Modelica.Thermal.FluidHeatFlow.Examples.SimpleCooling

Example: simple cooling circuit

Modelica.Thermal.FluidHeatFlow.Examples.SimpleCooling

Information

1st test example: SimpleCooling

A prescribed heat source dissipates its heat through a thermal conductor to a coolant flow. The coolant flow is taken from an ambient and driven by a pump with prescribed mass flow.
Results:

output	explanation	formula	actual steady-state value
dTSource	Source over Ambient	dtCoolant + dtToPipe	20 K
dTtoPipe	Source over Coolant	Losses / ThermalConductor.G	10 K
dTCoolant	Coolant's temperature increase	Losses * cp * massFlow	10 K

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium medium FluidHeatFlow.Media.Medium() Cooling medium

Temperature TAmb 293.15 Ambient temperature [K]

Type	Name	Default	Description
Medium	medium	FluidHeatFlow.Media.Medium()	Cooling medium
Temperature	TAmb	293.15	Ambient temperature [K]

Modelica definition

model SimpleCooling "Example: simple cooling circuit"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium medium=FluidHeatFlow.Media.Medium() 
    "Cooling medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  output Modelica.SIunits.TemperatureDifference dTSource=
    prescribedHeatFlow.port.T-TAmb "Source over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe=prescribedHeatFlow.port.T-pipe.heatPort.T 
    "Source over Coolant";
  output Modelica.SIunits.TemperatureDifference dTCoolant=pipe.dT 
    "Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=medium);
  Sources.VolumeFlow pump(
    medium=medium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  FluidHeatFlow.Components.HeatedPipe pipe(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=medium);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor(
    T(start=TAmb), C=0.1);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow;
  Modelica.Blocks.Sources.Constant volumeFlow(k=1);
  Modelica.Blocks.Sources.Constant heatFlow(k=10);
  Modelica.Thermal.HeatTransfer.Components.Convection convection;
  Modelica.Blocks.Sources.Constant thermalConductance(k=1);
equation 
  connect(ambient1.flowPort, pump.flowPort_a);
  connect(pump.flowPort_b, pipe.flowPort_a);
  connect(pipe.flowPort_b, ambient2.flowPort);
  connect(heatFlow.y, prescribedHeatFlow.Q_flow);
  connect(convection.solid, prescribedHeatFlow.port);
  connect(convection.solid, heatCapacitor.port);
  connect(pipe.heatPort, convection.fluid);
  connect(thermalConductance.y, convection.Gc);
  connect(volumeFlow.y, pump.volumeFlow);
end SimpleCooling;

Modelica.Thermal.FluidHeatFlow.Examples.ParallelCooling

Example: coolig circuit with parallel branches

Modelica.Thermal.FluidHeatFlow.Examples.ParallelCooling

Information

2nd test example: ParallelCooling

Two prescribed heat sources dissipate their heat through thermal conductors to coolant flows. The coolant flow is taken from an ambient and driven by a pump with prescribed mass flow, then splitted into two coolant flows connected to the two heat sources, and afterwards merged. Splitting of coolant flows is determined by pressure drop characteristic of the two pipes.
Results:

output	explanation	formula	actual steady-state value
dTSource1	Source1 over Ambient	dTCoolant1 + dTtoPipe1	15 K
dTtoPipe1	Source1 over Coolant1	Losses1 / ThermalConductor1.G	5 K
dTCoolant1	Coolant's temperature increase	Losses * cp * totalMassFlow/2	10 K
dTSource2	Source2 over Ambient	dTCoolant2 + dTtoPipe2	30 K
dTtoPipe2	Source2 over Coolant2	Losses2 / ThermalConductor2.G	10 K
dTCoolant2	Coolant's temperature increase	Losses * cp * totalMassFlow/2	20 K
dTmixedCoolant	mixed Coolant's temperature increase	(dTCoolant1+dTCoolant2)/2	15 K

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium medium FluidHeatFlow.Media.Medium() Cooling medium

Temperature TAmb 293.15 Ambient temperature [K]

Type	Name	Default	Description
Medium	medium	FluidHeatFlow.Media.Medium()	Cooling medium
Temperature	TAmb	293.15	Ambient temperature [K]

Modelica definition

model ParallelCooling 
  "Example: coolig circuit with parallel branches"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium medium=FluidHeatFlow.Media.Medium() 
    "Cooling medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  output Modelica.SIunits.TemperatureDifference dTSource1=
    prescribedHeatFlow1.port.T-TAmb "Source1 over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe1=prescribedHeatFlow1.port.T-pipe1.heatPort.T 
    "Source1 over Coolant1";
  output Modelica.SIunits.TemperatureDifference dTCoolant1=pipe1.dT 
    "Coolant1's temperature increase";
  output Modelica.SIunits.TemperatureDifference dTSource2=
    prescribedHeatFlow2.port.T-TAmb "Source2 over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe2=prescribedHeatFlow2.port.T-pipe2.heatPort.T 
    "Source2 over Coolant2";
  output Modelica.SIunits.TemperatureDifference dTCoolant2=pipe2.dT 
    "Coolant2's temperature increase";
  output Modelica.SIunits.TemperatureDifference dTmixedCoolant=ambient2.T_port-ambient1.T_port 
    "mixed Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=medium);
  Sources.VolumeFlow pump(
    medium=medium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  FluidHeatFlow.Components.HeatedPipe pipe1(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Components.HeatedPipe pipe2(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Components.IsolatedPipe pipe3(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=medium);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor1(
    T(start=TAmb), C=0.1);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow1;
  Modelica.Thermal.HeatTransfer.Components.Convection convection1;
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor2(
    T(start=TAmb), C=0.1);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow2;
  Modelica.Thermal.HeatTransfer.Components.Convection convection2;
  Modelica.Blocks.Sources.Constant volumeFlow(k=1);
  Modelica.Blocks.Sources.Constant heatFlow1(k=5);
  Modelica.Blocks.Sources.Constant heatFlow2(k=10);
  Modelica.Blocks.Sources.Constant thermalConductance1(k=1);
  Modelica.Blocks.Sources.Constant thermalConductance2(k=1);
equation 
  connect(ambient1.flowPort, pump.flowPort_a);
  connect(pump.flowPort_b, pipe1.flowPort_a);
  connect(pump.flowPort_b, pipe2.flowPort_a);
  connect(heatFlow2.y,prescribedHeatFlow2. Q_flow);
  connect(heatFlow1.y,prescribedHeatFlow1. Q_flow);
  connect(thermalConductance2.y, convection2.Gc);
  connect(thermalConductance1.y, convection1.Gc);
  connect(pipe1.heatPort,convection1. fluid);
  connect(convection2.fluid,pipe2. heatPort);
  connect(convection2.solid,prescribedHeatFlow2. port);
  connect(convection2.solid,heatCapacitor2. port);
  connect(convection1.solid,prescribedHeatFlow1. port);
  connect(convection1.solid,heatCapacitor1. port);
  connect(pipe2.flowPort_b,pipe3. flowPort_a);
  connect(pipe1.flowPort_b,pipe3. flowPort_a);
  connect(pipe3.flowPort_b,ambient2. flowPort);
  connect(volumeFlow.y, pump.volumeFlow);
end ParallelCooling;

Modelica.Thermal.FluidHeatFlow.Examples.IndirectCooling

Example: indirect cooling circuit

Modelica.Thermal.FluidHeatFlow.Examples.IndirectCooling

Information

3rd test example: IndirectCooling

A prescribed heat sources dissipates its heat through a thermal conductor to the inner coolant cycle. It is necessary to define the pressure level of the inner coolant cycle. The inner coolant cycle is coupled to the outer coolant flow through a thermal conductor.
Inner coolant's temperature rise near the source is the same as temperature drop near the cooler.
Results:

output	explanation	formula	actual steady-state value
dTSource	Source over Ambient	dtouterCoolant + dtCooler + dTinnerCoolant + dtToPipe	40 K
dTtoPipe	Source over inner Coolant	Losses / ThermalConductor.G	10 K
dTinnerColant	inner Coolant's temperature increase	Losses * cp * innerMassFlow	10 K
dTCooler	Cooler's temperature rise between inner and outer pipes	Losses * (innerGc + outerGc)	10 K
dTouterColant	outer Coolant's temperature increase	Losses * cp * outerMassFlow	10 K

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium outerMedium FluidHeatFlow.Media.Medium() Outer medium

Medium innerMedium FluidHeatFlow.Media.Medium() Inner medium

Temperature TAmb 293.15 Ambient temperature [K]

Type	Name	Default	Description
Medium	outerMedium	FluidHeatFlow.Media.Medium()	Outer medium
Medium	innerMedium	FluidHeatFlow.Media.Medium()	Inner medium
Temperature	TAmb	293.15	Ambient temperature [K]

Modelica definition

model IndirectCooling "Example: indirect cooling circuit"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium outerMedium=FluidHeatFlow.Media.Medium() 
    "Outer medium";
  parameter FluidHeatFlow.Media.Medium innerMedium=FluidHeatFlow.Media.Medium() 
    "Inner medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  output Modelica.SIunits.TemperatureDifference dTSource=
    prescribedHeatFlow.port.T-TAmb "Source over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe=prescribedHeatFlow.port.T-pipe1.heatPort.T 
    "Source over inner Coolant";
  output Modelica.SIunits.TemperatureDifference dTinnerCoolant=pipe1.dT 
    "inner Coolant's temperature increase";
  output Modelica.SIunits.TemperatureDifference dTCooler=innerPipe.heatPort.T-outerPipe.heatPort.T 
    "Cooler's temperature increase between inner and outer pipes";
  output Modelica.SIunits.TemperatureDifference dTouterCoolant=outerPipe.dT 
    "outer Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=outerMedium);
  Sources.VolumeFlow outerPump(
    medium=outerMedium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=outerMedium);
  Modelica.Thermal.HeatTransfer.Components.ThermalConductor
    thermalConductor(                                                        G=1);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor(
    T(start=TAmb), C=0.05);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow;
  FluidHeatFlow.Components.HeatedPipe pipe1(
    medium=innerMedium,
    m=0.1,
    T0=TAmb,
    V_flowLaminar=1,
    dpLaminar=1000,
    V_flowNominal=2,
    dpNominal=2000);
  FluidHeatFlow.Sources.AbsolutePressure absolutePressure(p=10000, medium=innerMedium);
  Sources.VolumeFlow innerPump(
    medium=innerMedium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  Modelica.Blocks.Sources.Constant heatFlow(k=10);
  Modelica.Blocks.Sources.Constant outerVolumeFlow(k=1);
  Modelica.Blocks.Sources.Constant innerVolumeFlow(k=1);
  Modelica.Blocks.Sources.Constant outerGc(k=2);
  Modelica.Blocks.Sources.Constant innerGc(k=2);
  FluidHeatFlow.Components.HeatedPipe outerPipe(
    medium=outerMedium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Components.HeatedPipe innerPipe(
    medium=innerMedium,
    m=0.1,
    T0=TAmb);
  Modelica.Thermal.HeatTransfer.Components.Convection innerConvection;
  Modelica.Thermal.HeatTransfer.Components.Convection outerConvection;
equation 
  connect(ambient1.flowPort, outerPump.flowPort_a);
  connect(prescribedHeatFlow.port, thermalConductor.port_a);
  connect(heatCapacitor.port, thermalConductor.port_a);
  connect(pipe1.heatPort, thermalConductor.port_b);
  connect(pipe1.flowPort_b, innerPump.flowPort_a);
  connect(absolutePressure.flowPort, pipe1.flowPort_a);
  connect(heatFlow.y, prescribedHeatFlow.Q_flow);
  connect(innerPump.flowPort_b, innerPipe.flowPort_a);
  connect(innerPipe.flowPort_b, absolutePressure.flowPort);
  connect(outerPump.flowPort_b, outerPipe.flowPort_a);
  connect(outerPipe.flowPort_b,ambient2. flowPort);
  connect(outerPipe.heatPort, outerConvection.fluid);
  connect(outerConvection.solid, innerConvection.solid);
  connect(innerConvection.fluid, innerPipe.heatPort);
  connect(innerGc.y, innerConvection.Gc);
  connect(outerGc.y, outerConvection.Gc);
  connect(outerVolumeFlow.y, outerPump.volumeFlow);
  connect(innerVolumeFlow.y, innerPump.volumeFlow);
end IndirectCooling;

Modelica.Thermal.FluidHeatFlow.Examples.PumpAndValve

Example: cooling circuit with pump and valve

Modelica.Thermal.FluidHeatFlow.Examples.PumpAndValve

Information

4th test example: PumpAndValve

The pump is running with half speed for 0.4 s, afterwards with full speed (using a ramp of 0.1 s).
The valve is half open for 0.9 s, afterwards full open (using a ramp of 0.1 s).
You may try to:

drive the pump with variable speed and let the valve full open to regulate the volume flow rate of coolant
drive the pump with constant speed and throttle the valve to regulate the volume flow rate of coolant

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium medium FluidHeatFlow.Media.Medium() Cooling medium

Temperature TAmb 293.15 Ambient temperature [K]

Type	Name	Default	Description
Medium	medium	FluidHeatFlow.Media.Medium()	Cooling medium
Temperature	TAmb	293.15	Ambient temperature [K]

Modelica definition

model PumpAndValve "Example: cooling circuit with pump and valve"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium medium=FluidHeatFlow.Media.Medium() 
    "Cooling medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  output Modelica.SIunits.TemperatureDifference dTSource=
    prescribedHeatFlow.port.T-TAmb "Source over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe=prescribedHeatFlow.port.T-pipe.heatPort.T 
    "Source over Coolant";
  output Modelica.SIunits.TemperatureDifference dTCoolant=pipe.dT 
    "Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=medium);
  FluidHeatFlow.Sources.IdealPump idealPump(
    medium=medium,
    m=0,
    T0=TAmb);
  FluidHeatFlow.Components.Valve valve(
    medium=medium,
    T0=TAmb,
    LinearCharacteristic=false);
  FluidHeatFlow.Components.HeatedPipe pipe(
    medium=medium,
    T0=TAmb,
    m=0.1);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=medium);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor(
    T(start=TAmb), C=0.1);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow;
  Modelica.Blocks.Sources.Constant heatFlow(k=10);
  Modelica.Thermal.HeatTransfer.Components.Convection convection;
  Modelica.Blocks.Sources.Constant thermalConductance(k=1);
  Modelica.Mechanics.Rotational.Sources.Speed speed(exact=true, useSupport=
        false);
  Modelica.Blocks.Sources.Ramp speedRamp(
    height=0.5,
    offset=0.5,
    duration=0.1,
    startTime=0.4);
  Modelica.Blocks.Sources.Ramp valveRamp(
    height=0.5,
    offset=0.5,
    duration=0.1,
    startTime=0.9);
equation 
  connect(pipe.flowPort_b, ambient2.flowPort);
  connect(heatFlow.y, prescribedHeatFlow.Q_flow);
  connect(convection.solid, prescribedHeatFlow.port);
  connect(convection.solid, heatCapacitor.port);
  connect(pipe.heatPort, convection.fluid);
  connect(thermalConductance.y, convection.Gc);
  connect(ambient1.flowPort, idealPump.flowPort_a);
  connect(idealPump.flowPort_b, valve.flowPort_a);
  connect(valve.flowPort_b, pipe.flowPort_a);
  connect(speedRamp.y, speed.w_ref);
  connect(valveRamp.y, valve.y);
  connect(speed.flange, idealPump.flange_a);
end PumpAndValve;

Modelica.Thermal.FluidHeatFlow.Examples.PumpDropOut

Example: cooling circuit with drop out of pump

Modelica.Thermal.FluidHeatFlow.Examples.PumpDropOut

Information

5th test example: PumpDropOut

Same as 1st test example, but with a drop out of the pump:
The pump is running for 0.2 s, then shut down (using a ramp of 0.2 s) for 0.2 s, then started again (using a ramp of 0.2 s).

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium medium FluidHeatFlow.Media.Medium() Cooling medium

Temperature TAmb 293.15 Ambient temperature [K]

Type	Name	Default	Description
Medium	medium	FluidHeatFlow.Media.Medium()	Cooling medium
Temperature	TAmb	293.15	Ambient temperature [K]

Modelica definition

model PumpDropOut "Example: cooling circuit with drop out of pump"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium medium=FluidHeatFlow.Media.Medium() 
    "Cooling medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  output Modelica.SIunits.TemperatureDifference dTSource=
    prescribedHeatFlow.port.T-TAmb "Source over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe=prescribedHeatFlow.port.T-pipe.heatPort.T 
    "Source over Coolant";
  output Modelica.SIunits.TemperatureDifference dTCoolant=pipe.dT 
    "Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=medium);
  Sources.VolumeFlow pump(
    medium=medium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  FluidHeatFlow.Components.HeatedPipe pipe(
    medium=medium,
    T0=TAmb,
    m=0.1);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=medium);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor(
    T(start=TAmb), C=0.1);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow;
  Utilities.DoubleRamp volumeFlow;
  Modelica.Blocks.Sources.Constant heatFlow(k=10);
  Modelica.Thermal.HeatTransfer.Components.Convection convection;
  Modelica.Blocks.Sources.Constant thermalConductance(k=1);
equation 
  connect(ambient1.flowPort, pump.flowPort_a);
  connect(pump.flowPort_b, pipe.flowPort_a);
  connect(pipe.flowPort_b, ambient2.flowPort);
  connect(heatFlow.y, prescribedHeatFlow.Q_flow);
  connect(convection.solid, prescribedHeatFlow.port);
  connect(convection.solid, heatCapacitor.port);
  connect(pipe.heatPort, convection.fluid);
  connect(thermalConductance.y, convection.Gc);
  connect(volumeFlow.y, pump.volumeFlow);
end PumpDropOut;

Modelica.Thermal.FluidHeatFlow.Examples.ParallelPumpDropOut

Example: cooling circuit with parallel branches and drop out of pump

Modelica.Thermal.FluidHeatFlow.Examples.ParallelPumpDropOut

Information

6th test example: ParallelPumpDropOut

Same as 2nd test example, but with a drop out of the pump:
The pump is running for 0.2 s, then shut down (using a ramp of 0.2 s) for 0.2 s, then started again (using a ramp of 0.2 s).

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium medium FluidHeatFlow.Media.Medium() Cooling medium

Temperature TAmb 293.15 Ambient temperature [K]

Type	Name	Default	Description
Medium	medium	FluidHeatFlow.Media.Medium()	Cooling medium
Temperature	TAmb	293.15	Ambient temperature [K]

Modelica definition

model ParallelPumpDropOut 
  "Example: cooling circuit with parallel branches and drop out of pump"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium medium=FluidHeatFlow.Media.Medium() 
    "Cooling medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  output Modelica.SIunits.TemperatureDifference dTSource1=
    prescribedHeatFlow1.port.T-TAmb "Source1 over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe1=prescribedHeatFlow1.port.T-pipe1.heatPort.T 
    "Source1 over Coolant1";
  output Modelica.SIunits.TemperatureDifference dTCoolant1=pipe1.dT 
    "Coolant1's temperature increase";
  output Modelica.SIunits.TemperatureDifference dTSource2=
    prescribedHeatFlow2.port.T-TAmb "Source2 over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe2=prescribedHeatFlow2.port.T-pipe2.heatPort.T 
    "Source2 over Coolant2";
  output Modelica.SIunits.TemperatureDifference dTCoolant2=pipe2.dT 
    "Coolant2's temperature increase";
  output Modelica.SIunits.TemperatureDifference dTmixedCoolant=ambient2.T_port-ambient1.T_port 
    "mixed Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=medium);
  Sources.VolumeFlow pump(
    medium=medium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  FluidHeatFlow.Components.HeatedPipe pipe1(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Components.HeatedPipe pipe2(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Components.IsolatedPipe pipe3(
    medium=medium,
    T0=TAmb,
    m=0.1);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=medium);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor1(
    T(start=TAmb), C=0.1);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow1;
  Modelica.Thermal.HeatTransfer.Components.Convection Convection1;
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor2(
    T(start=TAmb), C=0.1);
  Modelica.Thermal.HeatTransfer.Sources.PrescribedHeatFlow
    prescribedHeatFlow2;
  Modelica.Thermal.HeatTransfer.Components.Convection convection2;
  Utilities.DoubleRamp volumeFlow;
  Modelica.Blocks.Sources.Constant heatFlow1(k=5);
  Modelica.Blocks.Sources.Constant heatFlow2(k=10);
  Modelica.Blocks.Sources.Constant thermalConductance1(k=1);
  Modelica.Blocks.Sources.Constant thermalConductance2(k=1);
equation 
  connect(ambient1.flowPort, pump.flowPort_a);
  connect(pump.flowPort_b, pipe1.flowPort_a);
  connect(pump.flowPort_b, pipe2.flowPort_a);
  connect(heatFlow2.y,prescribedHeatFlow2. Q_flow);
  connect(heatFlow1.y,prescribedHeatFlow1. Q_flow);
  connect(thermalConductance2.y, convection2.Gc);
  connect(thermalConductance1.y, Convection1.Gc);
  connect(pipe1.heatPort, Convection1.fluid);
  connect(convection2.fluid,pipe2. heatPort);
  connect(convection2.solid,prescribedHeatFlow2. port);
  connect(convection2.solid,heatCapacitor2. port);
  connect(Convection1.solid,prescribedHeatFlow1. port);
  connect(Convection1.solid,heatCapacitor1. port);
  connect(pipe2.flowPort_b,pipe3. flowPort_a);
  connect(pipe1.flowPort_b,pipe3. flowPort_a);
  connect(pipe3.flowPort_b,ambient2. flowPort);
  connect(volumeFlow.y, pump.volumeFlow);
end ParallelPumpDropOut;

Modelica.Thermal.FluidHeatFlow.Examples.OneMass

Example: ccoling of one hot mass

Modelica.Thermal.FluidHeatFlow.Examples.OneMass

Information

7th test example: OneMass

A thermal capacity is coupled with a coolant flow. Different inital temperatures of thermal capacity and pipe's coolant get ambient's temperature, the time behaviour depending on coolant flow.

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium medium FluidHeatFlow.Media.Medium() Cooling medium

Temperature TAmb 293.15 Ambient temperature [K]

Temperature TMass 313.15 Inital temperature of mass [K]

Type	Name	Default	Description
Medium	medium	FluidHeatFlow.Media.Medium()	Cooling medium
Temperature	TAmb	293.15	Ambient temperature [K]
Temperature	TMass	313.15	Inital temperature of mass [K]

Modelica definition

model OneMass "Example: ccoling of one hot mass"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium medium=FluidHeatFlow.Media.Medium() 
    "Cooling medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  parameter Modelica.SIunits.Temperature TMass(displayUnit="degC")=313.15 
    "Inital temperature of mass";
  output Modelica.SIunits.TemperatureDifference dTMass=
    heatCapacitor.port.T-TAmb "Mass over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe=heatCapacitor.port.T-pipe.heatPort.T 
    "Mass over Coolant";
  output Modelica.SIunits.TemperatureDifference dTCoolant=pipe.dT 
    "Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=medium);
  Sources.VolumeFlow pump(
    medium=medium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  FluidHeatFlow.Components.HeatedPipe pipe(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=medium);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor(
    C=0.1, T(start=TMass));
  Modelica.Thermal.HeatTransfer.Components.ThermalConductor
    thermalConductor(                                                        G=1);
  Utilities.DoubleRamp volumeFlow(
    offset=0,
    height_1=1,
    height_2=-2);
equation 
  connect(ambient1.flowPort, pump.flowPort_a);
  connect(pump.flowPort_b, pipe.flowPort_a);
  connect(pipe.flowPort_b, ambient2.flowPort);
  connect(thermalConductor.port_a, heatCapacitor.port);
  connect(pipe.heatPort, thermalConductor.port_b);
  connect(volumeFlow.y, pump.volumeFlow);
end OneMass;

Modelica.Thermal.FluidHeatFlow.Examples.TwoMass

Example: cooling of two hot masses

Modelica.Thermal.FluidHeatFlow.Examples.TwoMass

Information

8th test example: TwoMass

Two thermal capacities are coupled with two parallel coolant flow. Different inital temperatures of thermal capacities and pipe's coolants get ambient's temperature, the time behaviour depending on coolant flow.

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Type Name Default Description

Medium medium FluidHeatFlow.Media.Medium() Cooling medium

Temperature TAmb 293.15 Ambient temperature [K]

Temperature TMass1 313.15 Inital temperature of mass1 [K]

Temperature TMass2 333.15 Inital temperature of mass2 [K]

Type	Name	Default	Description
Medium	medium	FluidHeatFlow.Media.Medium()	Cooling medium
Temperature	TAmb	293.15	Ambient temperature [K]
Temperature	TMass1	313.15	Inital temperature of mass1 [K]
Temperature	TMass2	333.15	Inital temperature of mass2 [K]

Modelica definition

model TwoMass "Example: cooling of two hot masses"
  extends Modelica.Icons.Example;
  parameter FluidHeatFlow.Media.Medium medium=FluidHeatFlow.Media.Medium() 
    "Cooling medium";
  parameter Modelica.SIunits.Temperature TAmb(displayUnit="degC")=293.15 
    "Ambient temperature";
  parameter Modelica.SIunits.Temperature TMass1(displayUnit="degC")=313.15 
    "Inital temperature of mass1";
  parameter Modelica.SIunits.Temperature TMass2(displayUnit="degC")=333.15 
    "Inital temperature of mass2";
  output Modelica.SIunits.TemperatureDifference dTMass1=
    heatCapacitor1.port.T-TAmb "Mass1 over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe1=heatCapacitor1.port.T-pipe1.heatPort.T 
    "Mass1 over Coolant1";
  output Modelica.SIunits.TemperatureDifference dTCoolant1=pipe1.dT 
    "Coolant1's temperature increase";
  output Modelica.SIunits.TemperatureDifference dTMass2=
    heatCapacitor2.port.T-TAmb "Mass2 over Ambient";
  output Modelica.SIunits.TemperatureDifference dTtoPipe2=heatCapacitor2.port.T-pipe2.heatPort.T 
    "Mass2 over Coolant2";
  output Modelica.SIunits.TemperatureDifference dTCoolant2=pipe2.dT 
    "Coolant2's temperature increase";
  output Modelica.SIunits.TemperatureDifference dTmixedCoolant=ambient2.T_port-ambient1.T_port 
    "mixed Coolant's temperature increase";
  FluidHeatFlow.Sources.Ambient ambient1(constantAmbientTemperature=TAmb, medium=medium);
  Sources.VolumeFlow pump(
    medium=medium,
    m=0,
    T0=TAmb,
    useVolumeFlowInput=true);
  FluidHeatFlow.Components.HeatedPipe pipe1(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Components.HeatedPipe pipe2(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Components.IsolatedPipe pipe3(
    medium=medium,
    m=0.1,
    T0=TAmb);
  FluidHeatFlow.Sources.Ambient ambient2(constantAmbientTemperature=TAmb, medium=medium);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor1(
    C=0.1, T(start=TMass1));
  Modelica.Thermal.HeatTransfer.Components.ThermalConductor
    thermalConductor1(                                                        G=1);
  Modelica.Thermal.HeatTransfer.Components.HeatCapacitor heatCapacitor2(
    C=0.1, T(start=TMass2));
  Modelica.Thermal.HeatTransfer.Components.ThermalConductor
    thermalConductor2(                                                        G=1);
  Utilities.DoubleRamp volumeFlow(
    offset=0,
    height_1=1,
    height_2=-2);
equation 
  connect(ambient1.flowPort, pump.flowPort_a);
  connect(pump.flowPort_b, pipe1.flowPort_a);
  connect(pump.flowPort_b, pipe2.flowPort_a);
  connect(pipe2.flowPort_b,pipe3. flowPort_a);
  connect(pipe1.flowPort_b,pipe3. flowPort_a);
  connect(pipe3.flowPort_b,ambient2. flowPort);
  connect(heatCapacitor2.port,thermalConductor2. port_a);
  connect(thermalConductor2.port_b,pipe2. heatPort);
  connect(pipe1.heatPort,thermalConductor1. port_b);
  connect(thermalConductor1.port_a, heatCapacitor1.port);
  connect(volumeFlow.y, pump.volumeFlow);
end TwoMass;

Automatically generated Fri Nov 12 16:31:43 2010.