Buildings.HeatTransfer
consists of models
for heat transfer.
The models have the same interface as models of the package
Modelica.Thermal.HeatTransfer.
This user's guide describes the model structure and how to instantiate models for heat transfer calculations.
The models that compute heat transfer in solids consist of data records for the materials and of models that compute the heat transfer. The data records are composed hierarchically and consist of data records that define material properties with thermal storage ( Buildings.HeatTransfer.Data.Solids) and of material properties of thermal resistors with no heat storage ( Buildings.HeatTransfer.Data.Resistances). These records are used to assemble layers that define the thermal properties of constructions ( Buildings.HeatTransfer.Data.OpaqueConstructions).
This layer definition is then used in models that compute the heat conduction. Like the materials, these models are assembled hierarchically. The simplest model is Buildings.HeatTransfer.ConductorSingleLayer for heat conduction through a single layer of material. If the material's specific heat capacity is non-zero, then the model solves the Fourier equation
dT ⁄ dt = k ⁄ (ρ c) d2T ⁄ dx2
If ρ c=0, then the model computes steady-state heat conduction
Q = A k (Ta-Tb)
The boundary conditions for this model are the temperatures and heat flow rates at the material interface.
The model Buildings.HeatTransfer.ConductorSingleLayer is then used to construct the heat conductor Buildings.HeatTransfer.ConductorMultiLayer that has multiple layers of material. Some layers may be computed transient (if ρ c > 0) and others are computed steady-state. The boundary conditions for this model are its surface temperatures and heat flow rates.
The model Buildings.HeatTransfer.ConductorMultiLayer is then used to build the construction Buildings.HeatTransfer.ConstructionOpaque that consists of Buildings.HeatTransfer.ConductorSingleLayer with a model for convective heat transfer at each side. To model convective heat transfer, instances of the model Buildings.HeatTransfer.Convection are used, which allow using a convective heat transfer coefficient that is fixed or that is a function of the temperature difference between the solid surface and the fluid.
This section describes how to specify materials, and how to instantiate models that compute the heat transfer. The section describes the syntax used to declare heat conduction models. Note that such syntax is typically generated through the use of a graphical user interface that will show fields that can be edited and that provide options for predefined data that may be used as-is or adjusted for a particular building.
Suppose we want to model a construction with a surface area of 20 m2 that consists of a 0.1 m insulation and 0.2 m concrete. This can be accomplished as follows.
First, we define the materials as
Buildings.HeatTransfer.Data.Solids.InsulationBoard insulation(x=0.1, nStaRef=4); Buildings.HeatTransfer.Data.Solids.Concrete concrete(x=0.2, nStaRef=4);
Here, we selected to use four state variables for each material layer.
Next, we define the construction. In the room model, the convention is that the first material layer faces the outside, and the last material layer faces the room-side. Therefore, the declaration for an exterior wall with insulation at the outside is
Buildings.HeatTransfer.Data.OpaqueConstructions.Generic wall(nLay=2, material={insulation,concrete});
(Note that nLay
must be set to the number of layers to allow
a Modelica translator to know how many layers there are prior to translating
the model.)
Alternatively, to model the insulation in steady-state, we can set its heat capacity to zero by declaring
Buildings.HeatTransfer.Data.Solids.InsulationBoard insulation(c=0, x=0.1, nStaRef=4);
Instead of specifying a material with specific heat capacity and setting c=0
,
materials from the library
Buildings.HeatTransfer.Data.Resistances can be used.
For example, for a floor with carpet, the declaration would be
Buildings.HeatTransfer.Data.Resistances.Carpet carpet; Buildings.HeatTransfer.Data.Solids.Concrete concrete(x=0.2, nStaRef=4); Buildings.HeatTransfer.Data.OpaqueConstructions.Generic floor(nLay=2, material={concrete, carpet});
To change the thermal resistance, we could have written
Buildings.HeatTransfer.Data.Resistances.Carpet carpet(R=0.3);
or
Buildings.HeatTransfer.Data.Resistances.Generic carpet(R=0.3);
Both definitions are identical.
If we want to use a construction that includes convective heat transfer coefficients,
and that conists of the material floor
defined above,
we can define
Buildings.HeatTransfer.ConstructionOpaque floorConstruction( A=10, layers = floor);
In the above example, carpet
is the material near
port_a
and
concrete
is the material near port_b
.
Alternatively, the layers of materials can be defined directly when instanciating the model that computes the heat conduction. For example,
Buildings.HeatTransfer.ConstructionOpaque floorConstruction( A=10, steadyStateInitial=true, redeclare Buildings.HeatTransfer.Data.OpaqueConstructions.Concrete200 layers( material={Data.Solids.Concrete(x=0.30, nStaRef=4)}), redeclare function qCon_a_flow = Buildings.HeatTransfer.Functions.ConvectiveHeatFlux.ceiling, redeclare function qCon_b_flow = Buildings.HeatTransfer.Functions.ConvectiveHeatFlux.floor);
This defines a floor with 10 m2 area.
It will be initialized at
steady-state. For the layers of materials, we used
one layer of Concrete200
, and redefined
its thickness to x=0.3 m. We also changed the number
of state variables that are used for the spatial discretization
of the term d2T ⁄ dx2
when solving the transient
heat conduction in this layer of material.
To compute the convective heat transfer, we chose
to use buoyancy-driven equations for the floor
(which is at surface b and hence assigned to qCon_b_flow
)
and the ceiling, which is at surface a.
If we are interested in modeling heat transfer through the construction without taking into account the convective heat transfer, we can define a construction model as
Buildings.HeatTransfer.ConductorMultiLayer conMul(A=20, layers=wall) "Construction with 20 m2 area";
Since there is already a predefined construction with the same material thickness in the library, we could have used the following identical definition:
Buildings.HeatTransfer.ConductorMultiLayer wall(A=20, redeclare Buildings.HeatTransfer.Data.OpaqueConstructions.Insulation100Concrete200 layers);